0=3t^2+73t+50

Solution for 0=3t^2+73t+50 equation:

0=3t^2+73t+50

We move all terms to the left:

0-(3t^2+73t+50)=0

We add all the numbers together, and all the variables

-(3t^2+73t+50)=0

We get rid of parentheses

-3t^2-73t-50=0

a = -3; b = -73; c = -50;
Δ = b2-4ac
Δ = -732-4·(-3)·(-50)
Δ = 4729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-\sqrt{4729}}{2*-3}=\frac{73-\sqrt{4729}}{-6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+\sqrt{4729}}{2*-3}=\frac{73+\sqrt{4729}}{-6}
$